c^2+c^2=8c-8

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Solution for c^2+c^2=8c-8 equation: 



c^2+c^2=8c-8

We move all terms to the left:

c^2+c^2-(8c-8)=0

We add all the numbers together, and all the variables

2c^2-(8c-8)=0

We get rid of parentheses

2c^2-8c+8=0

a = 2; b = -8; c = +8;
Δ = b2-4ac
Δ = -82-4·2·8
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{8}{4}=2$

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